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45x^2=84x-12
We move all terms to the left:
45x^2-(84x-12)=0
We get rid of parentheses
45x^2-84x+12=0
a = 45; b = -84; c = +12;
Δ = b2-4ac
Δ = -842-4·45·12
Δ = 4896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4896}=\sqrt{144*34}=\sqrt{144}*\sqrt{34}=12\sqrt{34}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-84)-12\sqrt{34}}{2*45}=\frac{84-12\sqrt{34}}{90} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-84)+12\sqrt{34}}{2*45}=\frac{84+12\sqrt{34}}{90} $
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